## CalculationsWhen finding how height the rocket went, you can use SOH CAH TOA.
Tan(33) = x/61 → Tan(33)*61 = x → 39.6m = x To find the velocity of the rocket we counted how many frames it took for the rocket to go past the reference post (extended to 2.4m). Which took 6 frames or 0.2 sec. to pass it. This helps us calculate the velocity by taking the hight (2.4m) and dividing it by the 0.2 seconds giving you 14m/s. During our experiment, we aimed to find out the force of gravity that was acting on our rocket with and without water. To do this, we utilized Newton's third law by inputting both masses into the force-mass formula. Our rocket's mass was 1.837kg with water and 0.337kg without water. We then multiplied these values by the acceleration due to gravity which is 9.81m/s^2. As a result, we found the force of gravity with water to be 18.02N and without water to be 3.31N. It's important to note that acceleration is due to the net force acting on an object, which means that gravity and drag will counteract the thrust force acting on the rocket during the launch. To find the force of thrust we first need to find the acceleration. We do this by Taking the velocity divided by time (14/0.2 = 70m/s^2). Then we find the net force by multiplying the mass (0.337 kg) by the acceleration (70m/s^2) which gives us 23.59N. Now for the last step to find trust, take the net force (23.59) + gravity (-9.81) = 33.4N of force. The flight time should be -½(9.81)t^2+14t+0.3 and where it intercepts the x on the right side giving us 2.88 seconds of flight but this does not take into account the backslider slowing it down. In science we learned the the parachute lowers the terminal velocity make drag = to the force of gravity. The force is 3.31N of drag and gravity. |